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Ages

The sum of the ages of Amar and his elder brother Abhay is 100 years.

The sum of the ages of Amar and his elder brother Abhay is 100 years. 1/15th of the product of their ages exceeds 3/5 th of Abhay's age by 132. Find Amar's age:

(A) 55

(B) 60

(C) 40

(D) 45

The ratio of the present ages of A to B is 5 : 3. The ratio of A's age 4 years ago

The ratio of the present ages of A to B is 5 : 3. The ratio of A's age 4 years ago to B's age 4 years hence is1 : 1. What is the ratio of A's age is 4 years hence to B's age 4 years ago?
(A)
3 : 2

(B) 7 : 5

The age of a person is four times the total ages of his two sons.

The age of a person is four times the total ages of his two sons. One decade hence his age will be twice of the total ages of his sons. Then what is the father's present age?

(A) 45

(B) 60

(C) 65

(D) 50

(E) 55

 

4 years ago ages of A B and C is in the ratio of 9 : 8 : 11. 4 years hence the sum of their ages is 80.

4 years ago ages of A, B and C are in the ratio of 9 : 8 : 11. 4 years hence the sum of their ages is 80. find the sum of the present ages of A and B?

(A) 30

(B) 42

(C) 54

(D) 17

(E) None of these

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